Have you ever seen graphs that appear to be identical but one is considerably more up and down extended than the other? This is all thanks to the vertical stretch enhancement technique.

The vertical stretch on a graph will draw the initial chart outside by a scale element given.

When a base function is multiplied by a specific factor, we can use the vertical stretch to plot the brand-new feature right away.


Before we get started on this makeover method, it’s a good idea to assess your knowledge of the following topics:





What does it mean to stretch vertically?


When a base chart is increased by a factor that is greater than 1, this is known as vertical stretch. The graph is dragged outside while the input values are preserved (or x). When we stretch the function vertically, we expect the y values on the chart to be further away from the x-axis.


The graph of f(x) as well as its transformations are shown in the diagram below. Why don’t we look at how f(x) changes when the result values are increased by a factor of 3 or 6?


The chart of f (x) expands by the same range factors when range factors of 3 and 6 are increased. We can also observe that their input values (in this case, x) remain unchanged; only the values for y were affected when f(x) was extended vertically.


What is the best way to generalize this rule?


A f(x) will stretch the basic function by a range variable when || > 1. Because the input values will not change, the graph’s coordinate factors will remain the same (x, ay).


This means that if f(x) = 5x + 1 is stretched up and down by a factor of 5, the resultant function will be 5 f. ( x). As a consequence, 5(5x + 1) = 25x + 5 is the resulting function.


How do I stretch a function vertically?


We can vertically expand a feature’s chart by drawing the curve outwards based on the scale variable provided. When stretching features vertically, there are a few considerations to keep in mind:


Assume that the values for x do not change, and the curve’s base will not change.


It indicates that when vertical stretches are applied to a base chart, the x-intercepts will surely remain the same.


Keep in mind the newly identified crucial spots, such as the graph’s new optimal point.


Why don’t we attempt expanding the feature y = x by an element of 2 up and down?


When we graph the brand-new feature y = 2 x, we’ve included some guide factors that show how they transform as well. What are our expectations for the brand-new graph?


It will almost definitely begin at the beginning. The y-coordinates will almost certainly grow by a factor of two. In addition, the graph will undoubtedly stretch by a factor of two.


The graph above shows how we can chart y = 2 x by stretching the y = x vertically by an element of two.


We may use the same method to expand other graphs and features both up and down. Why don’t we summarize what we’ve learned about vertical stretch thus far before moving on to further examples?


Definition of vertical stretch and residential properties in a nutshell


The effect of scaling a feature by a positive element, a, has now been discovered. When dealing with vertical stretches on charts, keep the following rules in mind:


When the range variable is greater than 1, a vertical stretch occurs.


Ensure that the y-coordinates are multiplied by the same scale element.


Keep the x-intercepts where they are.


The domain name for the up and down extended functionality will remain the same, but there will be a new array.


Let’s keep these useful memories in mind as we work through the remaining questions in this section. Ready?


Let’s get started with this method for progress!


1st example


The function g(x) is obtained by stretching f(x) = x2 + 1 up and down by a range variable of 3. Which of the following expressions for g(x) is correct?


312 + 1 Equals g(x).


g(x) = x2 + 3 g(x) = x2 + 3 g(x) =


312 + 3 Equals g(x).


3(x + 1) = g(x) 2.




We increase the base feature by its scale element when we stretch a feature up and down. As a result, we have g(x) = 3 f. ( x). Let’s make sure to distribute 3 to each term in f. ( x).


3(x2 + 1) = g(x).


32 + 3 Equals 32 + 3


This shows that 32 + 3 is the correct formula for g(x).